I'm having what sounds like this same issue on my 2014 Journey. Does anyone know if this repair is considered part of the powertrain warranty? It seems like it would be as the AWD system is part of Powertrain. I'm really hoping so as I have 2 months left.
So i brought the car in for a repair that replaced a tab in the steering wheel
Now it seems to be working 95% of the time YAHOOOO
Still need to smack sometimes but not as bad,Just hope that it stays this way
Thanks everyone for your insights
Yep. Adding LED's will make them full bright all the time as the turn on voltage for LED's is much lower than incandescent. But I also agree that it is not recommended. What makes you think they are not bright enough for their purpose?
The DRLs are fine, imho. I have noticed many DJs and the DRLs do their job. Make oncoming DJs more visible without being obnoxious. Making your DRLs brighter is just a way to cause people who don't know you to be annoyed by you.
Hey all. I was wonder if there was a way to make the DRLs brighter? I know the wattage is cut in half but didn't know if there was a resister or something I could remove it bypass... They don't seem bright enough for their purpose.
The tire diameter on the Journey is approximately 36.75" (225mm * 2 + 19") - give or take a few hundredths of an inch. If you have a brand new tire, and one that is worn to 50% of tread depth, the difference in diameter would be roughly .25" (4/32" *2 for total difference). That equates to a total tread length of 115.45" for a new tire, and 114.56" for the 50% worn, for a difference of just under 1".
What does that mean in real terms?
The wheels will spin at different speeds. The new tire will take 548.8 rotations per mile, while the worn tire will take 553.
For a new versus 50% worn tire, it looks like 4 extra rotations per mile for one tire versus the other. AWD must be incredibly sensitive.
For those who would like to see the math:
225 55/r19 tire = 225mm sidewall height or 8.85827"
diameter of tire = 8.85827" *2 + 19" = 36.71654"
assuming new tire with full 10/32" tread diameter from top of tread to top of tread = 36.71654", total tread length = 115.3483" (36.71654 * 3.14159)
50% worn tire is 6/32" (leaving 2/32" as the discard tread depth, leaving 8/32" of usable tread). tire diameter is 36.46654" total tread length at 50% wear is 114.56"
Edited to check my own math.